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Find the remainder when `1!+2!+3!+4!++n !`is divided by 15, if `ngeq5.` |
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Answer» Correct Answer - 3 Let, `N=1!+2!+3!+4!+5!+6!+..+n!` `implies (N)/(15)=(1!+2!+3!+4!+5!+..+n!)/(15)` `=(1!+2!+3!+4!)/(15)+(5!+6!+..+n!)/(15)` `=(33)/(15)`+integer (as 5!,6!,.. Are divisible by 15) Hence , remainder is 3. |
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