1.

Find the remainder when x^2-6x+3 is divided by (x+2)

Answer»

Solution : LET ` F(x)=x^2-6x+5` thus by remainder THEOREM the remainder when f(x) is divided by (x+2) [x-(-2)] is f(-2)
f(-2)=(-2)^2-6,(-2)+5=4+12+5=21`
Thus the remainder is 21


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