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InterviewSolution
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Find the remainder when `x^3-a x^2+6x-a` is divided by `x-a`. |
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Answer» From remainder theorem, we know that if `p(x)` is divided by `(x-a)`, then remainder will be `p(a).` Here, `p(x) = x^3-ax^2+6x-a` `p(a) = a^3 - a*a^2+6a -a = a^3 -a^3 +6a - a = 5a` So, remainder will be `5a`. |
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