1.

Find the remainder when `x^(3)-ax^(2)+6x-a` is divided by x-a.

Answer» The zero of x-a is a.
Let `p(x)=x^(3)-ax^(2)+6x-a`
So, `p(a)=a^(3)-a(a)^(2)+6a-a=a^(3)-a^(3)+5a`
`implies p(a)=5a`
`therefore` Required remainder =5a


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