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Find the remainder when `x^(3)-ax^(2)+6x-a` is divided by x-a. |
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Answer» The zero of x-a is a. Let `p(x)=x^(3)-ax^(2)+6x-a` So, `p(a)=a^(3)-a(a)^(2)+6a-a=a^(3)-a^(3)+5a` `implies p(a)=5a` `therefore` Required remainder =5a |
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