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Find the resistivity of a conductor having length 2m area of cross section 1.4 x 10 raise to the power -6 and resistance of 0.04 ohm. |
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Answer» R = \(\frac{\rho l}A\) \(\rho = \frac{RA}l\) \(\rho=\frac{0.04\times1.4\times10^{-6}}2\) \(\rho = \) 0.028 x 10-6 \(\Omega\)m |
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