1.

Find the roots of quadratic equation 9x2 + 6x + 1 = 0

Answer»

Given

9x2 + 6x + 1 = 0

⇒ 9x2 + 3x + 3x + 1 = 0

⇒ 3x(3x + 1) + 1(3x + 1) = 0

⇒ (3x + 1) (3x + 1) = 0

⇒ 3x + 1 = 0 or 3x + 1 = 0

⇒ x = -1/3 or x = -1/3

Hence -1/3 is the root of the equation 9x2 + 6x + 1 = 0



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