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Find the roots of quadratic equations x2 - 4x + 1 = 0 |
Answer» x2 - 4x + 1 = 0 ⇒ x2 - 4x = -1 ⇒ x2 - 2 \(\times\)x \(\times\)2 + 22 = - 1 + 22 (Adding 22 on both sides) ⇒ (x - 2)2 = - 1 + 4 = 3 ⇒ x - 2 = ±√3 ⇒ x - 2 = √3 or x - 2 = - √3 ⇒ x = 2 + √3 or x = 2 -√3 Hence, 2 + √3 and 2 - √3 are the roots of the given equation. |
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