1.

Find the roots of quadratic equations x2 - 6x + 3 = 0

Answer»

x2 - 6x + 3 = 0

⇒ x2 - 6x = - 3

⇒ x2 - 2 \(\times\)x \(\times\)3 + 32 = - 3 + 32   (Adding 32 on both sides)

⇒ (x - 3)2 = - 3 + 9 = 6

⇒ x  - 3 = ± √6  (Taking square root on the both sides)

⇒ x - 3 = √6 or x - 3 = - √6

⇒ x = 3 + √6 or x = 3 - √6

Hence, 3 + √6 and 3 - √6 are the roots of the given equation.


Discussion

No Comment Found

Related InterviewSolutions