Find the roots of the equation ax2 + (4a2 – 3b)x – 12ab = 0. – InterviewSolution

InterviewSolution

1.

Find the roots of the equation ax2 + (4a2 – 3b)x – 12ab = 0.

Answer»

Given equation is ax²+ (4a²– 3b)x – 12ab = 0

⇒ ax²+ 4a²x – 3bx – 12ab = 0

⇒ ax(x + 4a) – 3b(x + 4a) = 0

⇒ (x + 4a)(ax – 3b) = 0

Now, either x + 4a = 0 ⇒ x = -4a

Or, ax – 3b = 0 ⇒ x = \(\frac{3b}{a}\)

Thus, the roots of the given quadratic equation are x = \(\frac{3b}{a}\) and -4a respectively.

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