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Find the roots of the following quadratic equation by factorisation,2x2 – x + 1/8 = 0 |
Answer» Given: 2x2 – x + 1/8 = 0 ⇒ \(\frac{16x^2 - 8x +1}{8}\) = 0 ⇒ 16x2 – 8x + 1 =0 ⇒ 16x2 – 4x – 4x + 1 = 0 ⇒ 4x(4x – 1) – l(4x – 1) = 0 ⇒ (4x – 1) (4x – 1) – 0 ⇒ 4x – 1 = 0 ⇒ 4x = 1 ⇒ x = 1/4, 1/4 are the roots of given Q.E. |
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