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Find the roots of the followingquadratic equation. If they asexist, using the quadratic formulaof shrichas Aekarya.tot23, X+0,22-2 |
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Answer» 1/x + 1/ x -2 =3;; x-2-x/x(x-2)=3; -2/ x^2-2x; =3; -2=3x^2-6x+2; 1/x-1/x-2=3x-2-x/x^2-2x=33x^2-6x= -23x^2-6x+2=0according to shridhar acharya x = -b+-√b^2-4ac/2a a= 3, b= -6, C= 2x= 6+-√36-4×3×2/2×3 = 6+-√36-24/6= 6+-√12/6= 6+-2√3/6x= +6+2√3/6=2(3+√3)/6=3+√3/3x= 6-2√3/6=2(3-√3)/6=3-√3/2 |
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