1.

Find the roots of the quadratic equation `6x^2-x-2=0`.

Answer» equation is `6x^2 - x-2=0 `
let `alpha & beta` be two terms such that
`alpha+ beta= -x`
`alpha* beta= (6x^2)(-2) = -12x^2`
`alpha= -4x & beta= 3x`
`6x^2 - 4x+3x-2=0`
`2x[3x-2]+1[3x-2]=0`
`(2x+1)(3x-2)=0`
`2x+1=0`
`x=-1/2` answer
and `3x-2=0`
`x=2/3` answer


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