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Find the rth term of an A.P. sum of whose first n terms is 2n + 3n2.[Hint: an = Sn – Sn–1] |
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Answer» Sum of first n terms be Sn given as Sn = 2n + 3n2 We have to find the rth term that is ar Using the hint: the nth term is given as an = Sn – Sn-1 ⇒ ar = Sr – Sr-1 Using Sn = 2n + 3n2 ⇒ ar = 2r + 3r2 – (2(r – 1) + 3(r – 1)2) ⇒ ar = 2r + 3r2 – (2r – 2 + 3(r2 – 2r + 1)) ⇒ ar = 2r + 3r2 – (2r – 2 + 3r2 – 6r + 3) ⇒ ar = 6r – 1 Hence the rth term is 6r – 1 |
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