Saved Bookmarks
| 1. |
Find the scalar product of the following pairs of vectors and the angle between them. hati-hatj and hatj+hatk |
|
Answer» SOLUTION :Let `veca = hati-hatj, VECB = hatj+hatk` Then `|veca| = sqrt2, |vecb| = sqrt2` Now `veca.vecb = 1xx0-1xx1+0xx1 = 0-1+0 = -1` if `theta` is the ANGLE between `veca` and `vecb` then `theta = cos^(-1) ((veca.vecb)/(|veca||vecb|))` =`cos^(-1)(-(1)/(sqrt2 sqrt2)) = cos^(-1) (-1/2) = (2pi)/3`. |
|