Saved Bookmarks
| 1. |
Find the scalar product of the following pairs of vectors and the angle between them. 2hati-3hatj+6hatk and 2hati-3hatj-5hatk |
|
Answer» Solution :LET `veca = 2hati-3hatj+6hatk, vecb = 2hati-3hatj-5hatk` Then `|veca| = sqrt(4+9+36) = 7` `|vecb| = sqrt(4+9+25) = sqrt(38)` `veca.vecb = 4+9-30 = -17` If `THETA` is the angle between `veca` and `vecb` then `theta = cos^(-1) ((veca.vecb)/(|veca||vecb|)) = cos^(-1) ((-17)/(7sqrt(38)))`. |
|