Find the side lengths of a triangle with a perimeter of 120 in. and th

1.	Find the side lengths of a triangle with a perimeter of 120 in. and the ratio of thesides as 3:4:5.
Answer» ANSWER: LET the sides of TRIANGLE ABC be 3x , 4x and 5X And it's perimeter is 120 perimeter of triangle = Sum of all sides 120 = 3x + 4x + 5x 120 = 12x 120÷12 = x 10 = x 1st side = 3x = 3×10 = 30 2nd side = 4x = 4×10 = 40 3rd side = 5×10 = 50

Find the side lengths of a triangle with a perimeter of 120 in. and the ratio of thesides as 3:4:5.

Answer»

LET the sides of TRIANGLE ABC be 3x , 4x and 5X

And it's perimeter is 120

perimeter of triangle = Sum of all sides

120 = 3x + 4x + 5x

120 = 12x

120÷12 = x

10 = x

1st side = 3x = 3×10

= 30

2nd side = 4x = 4×10 = 40

3rd side = 5×10 = 50