1.

Find the slope of the tangent to curve y=x^3-x+1 at the point whose x-coordinate is 2.

Answer»

SOLUTION :`y=x^3-x+1(DY)/DX=3x^2-1` SLOPE of the TANGENT `=(dy)/dx]_(x=2)=3xx2^2-1=11`


Discussion

No Comment Found

Related InterviewSolutions