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| 1. |
Find the slope of the tangent to the curve y=x^3-3x+2 at the point whose x-coordinate is 3. |
| Answer» SOLUTION :`y=x^3-3x+2(DY)/DX=3x^2-3` SLOPE of the TANGENT `=(dy)/dx]_(x=3)=3xx3^2-3=24` | |