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Find The Smallest Number Which Leaves A Remainder Of 2, When Divided By 3, 4, 5, And 6? |
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Answer» Taking L.C.M of 3, 4, 5 and 6 = 60. Hence, 60 is the number which is completely DIVISIBLE by these number, but we need that number which leaves the remainder of 2 while dividing by these number, so the REQUIRED number is 62. Taking L.C.M of 3, 4, 5 and 6 = 60. Hence, 60 is the number which is completely divisible by these number, but we need that number which leaves the remainder of 2 while dividing by these number, so the required number is 62. |
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