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Find The Smallest Number Which Leaves A Remainder Of 2, When Divided By 3, 4, 5, And 6?

Answer»

Taking L.C.M of 3, 4, 5 and 6 = 60.

Hence, 60 is the number which is completely DIVISIBLE by these number,

but we need that number which leaves the remainder of 2 while dividing by these number,

so the REQUIRED number is 62.

Taking L.C.M of 3, 4, 5 and 6 = 60.

Hence, 60 is the number which is completely divisible by these number,

but we need that number which leaves the remainder of 2 while dividing by these number,

so the required number is 62.



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