1.

Find the smallest number which when divided by 5, 6, 7 and 9 leaves a remainder 4, but when divided by 8 leaves no remainder?1). 12602). 12703). 12644). 1258

Answer»

LCM of 5,6,7,9 is 630

Check STEP 1:630*k +4 

Step 2: 630*2+4 =1264 and divide by 8 ie) 1264 /8 = 158 so the remainder is zero ,hence the answer is 1264. Or move from option which ONE is divisible by the GIVEN divisor.



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