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Find the smallest perfect square number divisible by 12, 15 and 18.1. 9002. 16003. 4004. 100 |
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Answer» Correct Answer - Option 1 : 900 Given: The numbers are 12, 15 and 18. Concept used: To make N(LCM) = xa × yb × zc perfect square. (where x, y and z are prime numbers and a, b and c are integers) Multiply the number by the same number whose power is odd. Calculations: 12 = 22 × 31 15 = 31 × 51 18 = 21 × 32 N = 22 × 32 × 51 Multiply N by 5 to get perfect square, 5N = 22 × 32 × 52 = 900 ∴ The smallest perfect square number divisible by 12, 15 and 18 is 900. |
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