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Find the solution of the linear equation x+2y =8 which represents a point on (i) X-axis (ii) Y-axis |
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Answer» We have, x+2y=8 (i) When the point is on the X-axis, then put y=0 in Eq. (i) we get `x+2xx0=8` `implies` x=8 Hence, the required point is (8,0). (ii) When the point is on the Y-axis, then put x=0 in Eq. (i), we get 0+2y=8 `implies " " y=(8)/(2)=4` Hence, the required point is (0,4). |
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