1.

Find the solution of the linear equation x+2y =8 which represents a point on (i) X-axis (ii) Y-axis

Answer» We have, x+2y=8
(i) When the point is on the X-axis, then put y=0 in Eq. (i) we get
`x+2xx0=8`
`implies` x=8
Hence, the required point is (8,0).
(ii) When the point is on the Y-axis, then put x=0 in Eq. (i), we get
0+2y=8
`implies " " y=(8)/(2)=4`
Hence, the required point is (0,4).


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