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Find the solution of x^2≡ 16 mod 23(a) x = 6 and 17(b) x = 4 and 19(c) x = 11 and 12(d) x = 7 and 16This question was posed to me during an interview.The query is from Number Theory topic in chapter More Number Theory of Cryptograph & Network Security

Answer»

The correct choice is (B) x = 4 and 19

To explain: a=16(16)^((23+1)/4) ≡ (16)^6≡1(QR and there is SOLUTION).

x ≡ ±16(23 + 1)/4 (mod 23) ≡±4i.e. x = 4 and 19.



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