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Find the square root of `4^(6n^(2)) (25)^((a)/(2)) 9^(b^(4))` .A. `4^(3n^(2)) 5^((a)/(4)) 3^(b^(2))`B. `2^(6n^(2)) 5^((a)/(2)) 3^(b^(2))`C. `2^(6n^(2)) 5^((a)/(2)) 3^(b^(4)) `D. `4^(3n) 5^(a) 3^(b^(2))` |
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Answer» Correct Answer - C `sqrt(4^(6n^(2)) . (25)^((n)/(2)).9^(b^(4)))` `=[4^(6n^(2)) (25)^((a)/(2)).9^(b^(4))]^((1)/(2))` `=[2^(2 xx 6n^(2)) 5^(2 xx (a)/(2)) 3^(2xx b^(4))]^((1)/(2))` =` 2^(6n^(2)) . 5^((a)/(2)). 3^(b ^(4)) ` ltbr. Hence , the correct option is (c) . |
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