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Find the square root of : 4a2 + 9b2 + c2 - 12ab + 6bc - 4ac(a) (2a + 3b - c)(b) (2a - 3b + c)(c) (-2a + 3b + c)(d) (-2a + 3b + c) |
Answer» (c) (-2a + 3b + c) 4a2 + 9b2 + c2 - 12ab + 6bc - 4ac = (-2a)2 + (3b)2 + c2 + 2 x (-2a) x 3b + 2 x 3b x c + 2 x (-2a) x c = (-2a + 3b + c)2 ∴ Reqd. sq. root = –2a + 3b + c |
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