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Find the square root of: (i) 23394/729(ii) 2151/169(iii) 10151/225 |
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Answer» (i) \(23\frac{394}{729}\) √(23394/729) = √(17161/729) = \(4\frac{23}{27}\) (ii) \(21\frac{51}{169}\) = \(\sqrt{21\frac{51}{169}}\) = √(3600/169) = 60/13 = \(4\frac{8}{13}\) (iii) \(10\frac{151}{225}\) = \(\sqrt{10\frac{151}{225}}\) = √(2401/225) = 49/15 = \(3\frac{4}{15}\) |
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