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Find the sum of all Natural Numbers between 1 and 100 divisible by 2 or 5. I have Done the following: Sum of digits divisible by 2 (1)+ Sum of digits divisible by 5(2) - Sum of digits divisible by by both 2 and 5i.e. 10(3). No of terms for (1)= 49 No of terms for (2)= 19 No of terms for (3)= 9 My answer is 2950 but is given 3050 in the book. |
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Answer» Find the sum of all Natural Numbers between 1 and 100 divisible by 2 or 5. I have Done the following: Sum of digits divisible by 2 (1)+ Sum of digits divisible by 5(2) - Sum of digits divisible by by both 2 and 5i.e. 10(3). No of terms for (1)= 49 No of terms for (2)= 19 No of terms for (3)= 9 My answer is 2950 but is given 3050 in the book. |
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