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Find the sum of all odd numbers between 100 and 200. |
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Answer» The series formed by odd numbers lying between 100 and 200 is `101+103+105+.....+199` Here, a=101, `d=103-101=105-103=2` Let `a_(n)=199` `rArr 101+(n-1)2=199` `rArr (n-1)2=98 rArr n-1=49` ltbtgt `rArr n=50` Now, `S_(50)=(50)/(2)(101+199)=7500` |
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