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Find the sum of all two digits numbers divisible by 4.1). 11882). 11823). 11864). 1184 |
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Answer» Required NUMBERS are: 12, 16, 20, ……, 96 This is an ARITHMETIC progression series in which FIRST term, a = 12 difference, d = 4 and last term l = 96. LET no. of terms in this series is n. ⇒ l = a + (n – 1) × d ⇒ 96 = 12 + (n – 1) × 4 ⇒ (n – 1) × 4 = 84 ⇒ n – 1 = 21 ⇒ n = 22 ∴ required sum = (n/2) × (a + l) = (22/2) × (12 + 96) = 11 × 108 = 1188 |
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