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Find the sum of coefficients of x⁴ and x in the polynomial f(x) = −4x5 + x4 + 2x2 − 7x 8 + 6 |
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Answer» Answer: First expand the term (1+2x) 4 by binomial EXPANSION. (1+2x) 4 = 4 C 0
(1) 4 (2x) 0 + 4 C 1
(1) 3 (2x) 1 + 4 C
(1) 2 (2x) 2 + 4 C 3
(1) 1 (2x) 3 + 4 C 4
(1) 0 (2x) 4
=1+8x+24x 2 +32x 3 +16x 4 (1) Now expand the term (2−x) by binomial expansion, (2−x) 5 = 5 C 0
(2) 5 (x) 0 − 5 C 1
(2) 4 (x) 1 + 5 C 2
(2) 3 (x) 2 − 5 C 3
(2) 2 (x) 3 + 5 C 4
(2) 1 (x) 4 − 5 C 5
(2) 0 (x) 5
=32−80x+80x 2 −40x 3 +10x 4 −x 5 (2) Multiply the coefficients of those powers which can give the term x 4 and then add from equation (1) and (2). =1×10+8(−40)+24(80)+32(−80)+16(32) =−438 Therefore, the COEFFICIENT of x 4 is −438. Step-by-step explanation: here is your answer |
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