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Find the sum of n terms of the series 1.2.4 + 2.3.5 + 3.4.6 + … (a) n(n + 1)(n + 2) (b) (n(n + 1)/12)(3n2 + 19n + 26) (c) ((n + 1)(n + 2)(n + 3))/4 (d) (n2 (n + 1)(n + 2)(n + 3))/3 |
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Answer» In order to solve such problems in the examination, the option-based approach is the best. Even if you can find out the required expression mathematically, it is advisable to solve through the options as this will end up saving a lot of time for you. Use the options as follows: If we put n = 1, we should get the sum as 1.2.4 = 8. By substituting n = 1 in each of the four options we will get the following values for the sum to 1 term: Option (a) gives a value of: 6 Option (b) gives a value of: 8 Option (c) gives a value of: 6 Option (d) gives a value of: 8 From this check we can reject the options (a) and (c). Now put n = 2. You can see that up to 2 terms, the expression is 1.2.4 + 2.3.5 = 38. The correct option should also give 38 if we put n = 2 in the expression. Since, (a) and (c) have already been rejected, we only need to check for options (b) and (d). Option (b) gives a value of 38. Option (d) gives a value of 80. Hence, we can reject option (d) and get (b) as the answer |
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