1.

Find the sum of the following APs:(1) 2, 7, 12, ..., to 10 terms(ii) - 37,-33-29.., to 12 terms(ii) 0.6, 1.7,2.8, , to 100 terms(iv)toll terms15' 12' 10i,--,

Answer»

i) 10/2(2(2)+9(5))=5(4+45)=5(49)=245ii) 12/2(2(-37)+11(4))=6(-74+44)=6(-30)=-180iii) 100/2(2(0.6)+99(1.1))=50(1.2+108.9)=50(110.1)=5505iv)11/2(2(1/15)+10(1/12-1/15))=11/2(2/15+10(3/(15×12)))=11/2(2/15+10(1/60))=11/2(2/15+1/6)=11/2(27/90)=11*3/(10*2)=33/20



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