1.

Find the sumsum_(0leiltjlen)1.

Answer»

SOLUTION :`underset(0leiltjlen)(sumsum1)=(sum_(i=1)^(n)sum_(j=1)^(n)1-sum_(i=j)SUM1)/2`
`=((sum_(j=1)^(n)1)(sum_(j=1)^(n)1)-sum_(j=1)^(n))/2`
`=(n^(2)-n)/2`
`=(n(n-1))/2`


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