Find the temperature of an oven if it radiates 8.28 cal per second through an opening, whose area is6.1cm^(2). Assume that the radiation is close to that of a black body.

Find the temperature of an oven if it radiates 8.28 cal per second thr

1.	Find the temperature of an oven if it radiates 8.28 cal per second through an opening, whose area is6.1cm^(2). Assume that the radiation is close to that of a black body.
Answer» SOLUTION :The emittance of the oven (the ENERGY radiated in ONE second by unit SURFACE area) is `E=(8.28cal//s)/(6.1cm^(2))` = `(8.28xx4.2J//s)/(6.1xx10^(-4)m^(2))=5.7xx10^(4)"watt"//m^(2)` From stefan - BOLTZMANN formula `E=sigma-T^(4)`, where `sigma=5.67xx10^(-8)W//m^(2).K^(4)` `T^(4)=E/sigma=(5.7xx10^(4))/(5.67xx10^(-8))=1xx10^(12)K^(4)` `thereforeT=10^(3)K=1000K`.