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Find the terminal velocity of a steel ball 2 mm in diameter falling through glycerine. Relative density of steel is 8, relative density of glycerine is 1.3 and viscosity of glycerine is 8.3 poise. |
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Answer» Solution :`v = 2/9 (r^2)/(eta) (rho - rho.) g = 2/9 ((0.1)^2)/(8.3 (8 - 1.3) XX 9.8` `v = 1.758 cm s^(-1)` |
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