Saved Bookmarks
| 1. |
Find the time required for a `50 Hz` alternating current to change its value from zero to the rms value. |
|
Answer» Let to equation of aternating current be `I = I_(0) sin omega t = I_(0) sin 100 pi xx 0 = 0` At time t, `I = I_(rms) = (I_(0))/(sqrt 2)` `:. (I_(0))/(sqrt 2) = I_(0) sin omega t` `sin omega t = (1)/(sqrt 2) = sin pi // 4` `t = (pi)/(4 omega) = (pi)/(4 xx 2 pi xx 50) = (1)/(400) s` `t = (1)/(400) s = 2.5 xx 10^(-3) s` |
|