1.

Find the time `t_0` when x-coordinate of the particle is zero.

Answer» Correct Answer - B::C::D
`8.25 s`
(b) Total displacement =`4+4-16-32-16=-56 m`
This is also equal to `x_f-x_i=-46-10=-56 m`
Total distance=`4+4+16+32+16=72 m`
Total time =`16s`
Now, average velocity=total displacement/total time
` = -56/16=-3.5 m//s`
average speed =`("total distance")/("total time")`
`=72/16=4.5 m//s`
(c) Average acceleration=`(Delta v)/(Delta t)`
`=(v_f-v_i)/(Delta t)=(v_(8 sec)-v_(2 sec))/(8-2)`
`=(-8-4)/6=-2 m//s^2`


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