Saved Bookmarks
| 1. |
Find the torque about the point 'A' in the following diagram |
Answer» Solution : (1) Torque DUE to 20N : about A=O (2) Torque due to 10N`=10xx0.8=8N` (C wise) Torque due to 25N `=(25sin25^(@))` (AC wise) `=25xx0.8sin25^(@)` `=25xx0.8xx0.4225=845nm` Net torque `=0-8N`(CW)+8.45(ACW) =0.45 anticlockwise |
|