InterviewSolution
Saved Bookmarks
| 1. |
Find the total number of nine-digit numbers that can be formed using thedigits 2, 2, 3, 3, 5, 5, 8, 8, 8 so that the odd digitoccupy the even places. |
| Answer» Odd digits 3,3,5,5 occupy four even places in `4!//(2!2!)=6` ways. Rest five digits 2,2,8,8,8 occupy rest five places in `5!//(2!3!)=10` ways. Hence, the total number of ways is `6xx10=60`. | |