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Find the total number of terms in (1+x+x^2)^3. |
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Answer» Solution :`(1+x)^2=1+x^2+2x` `(1+x)^3=1+3x+3x^2+x^3` `(1+x)^4=1+4x+6x^2+4x^3+x^4` `(1+x+x^2)^2=1+2x+3x^2+2x^3+x^4` `(1+x+x^2)^3=1+3x+6x^2+7x^3+6x^4+3x^5+x^6` This shows that total NUMBER of TERMS in `(1+x+x^2+….x^n)^m=(m.n)+1` |
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