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Find the unit circle concentric with the circle x2 + y2 – 8x + 4y = 8. |
Answer» Here unit circle ⇒ r = 1 & Center of concentric circle x2 + y2 – 8x + 4y – 8 = 0 C = (4, -2) & r = \(\sqrt{(-4)^2 + (2)^2 - (C0} = \sqrt{16 + 4 - C} = 1\) ⇒ 20 – C = 19 ⇒ C = 19 ∴ The Equation of the circle is x2 + y2 – 8x + 4y + 19 = 0. |
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