1.

Find the unit circle concentric with the circle x2 + y2 – 8x + 4y = 8.

Answer»

Here unit circle ⇒ r = 1 

& Center of concentric circle x2 + y2 – 8x + 4y – 8 = 0

C = (4, -2) & r 

\(\sqrt{(-4)^2 + (2)^2 - (C0} = \sqrt{16 + 4 - C} = 1\)

⇒ 20 – C = 19 

⇒ C = 19 

∴ The Equation of the circle is x2 + y2 – 8x + 4y + 19 = 0.



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