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Find the `V_(ab)` in an electric field `E=(2hati+3hatj+4hatk)N/C`, where `r_a=(hati-2hatj+hatk)m` and `r_b=(2hati+hatj-2hatk)m` |
Answer» Correct Answer - A Here the given field is uniform (constant) so Using `dV=-E.dx` `or V_(ab)=V_a-V_b=-int_b^aE.dr` `=-int_((2,1,-2))^((1,-2,1))(2hati+3hatj+4hatk).(dxhati+dyhatj+dzhatk)` `-int_((2,1,-2))^((1,-2,1))(2 dx+3dy+4dz)` `-[2x+3y+4z]_((2,1,-2))^((1,-2,1))` `=-1V` |
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