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Find the value k, such that the following quadratic equation has equal roots(k-12):2-2(k-12)x + 2 = 0 |
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Answer» For equal roots discriminant =0Hence b^2-4ac=0b=-2(k-12)c=2a=(k-12)Henceb^2-4ac=4(k-12)^2-8(k-12)=0hence(k-12)-8=0k-12-8=0k-20=0k=20 |
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