1.

Find the value of ( 1 / √10 + √10 ) When √10 = 3.162

Answer»

1/√10 x √10/√10 + √10
= √10/10 + √10
= (√10+10√10)/10
= 11√10/10
= 11 x 3.162/10
= 3.4782

\(\frac{1}{\sqrt{10}} + \sqrt{10}\)

\(\frac{1}{\sqrt{10}} \times \frac{\sqrt{10}}{\sqrt{10}} + \sqrt{10}\)

\(\frac{\sqrt{10}}{10} + \sqrt{10}\)

\(\sqrt{10} + 10\sqrt{10}\over10\)

\(11\sqrt{10} \over10\)

= \(11 \times 3.162\over10\)

= \(34.782\over10\)

= 3.4782



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