Find the value of `(-1)^(301)+(-1)^(302)+(-1)^(303)+.......+(-1)^(400) – InterviewSolution

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1.	Find the value of `(-1)^(301)+(-1)^(302)+(-1)^(303)+.......+(-1)^(400)`.A. 1B. 101C. 100D. 0
Answer» Correct Answer - D We know `(-1)^x` `=-1`, when x is odd. `=1` , when x is even. `therefore (-1)^(301)+(-1)^(302)+....+(-1)^(400)` `=(-1)+1+(-1)+1+...(100 " terms") =0` Hence, the correct options is (d).

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