1.

Find the value of 1/x for the following values of x : (a)[-5 , -1](b)(3,6)(c )(-2 , 3)(d )(-oo , -2]( e)[-3,4]

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Solution :(a) `2 lt X lt 5`
` rArr1/2 gt 1/xgt1/5`
`RARR 1/(x)in(1/5,1/2)`
(b) `-5 le x lt -1`
`rArr-1/5ge 1/x gt-1`
`rArr1/(x)in(-1,-1/5]`
(c) `x gt3 or 3 lt x lt oo`
`x le -2 or - oo lt x le-2`
`rArr0 gt1/xge-1/2`
`rArr1/x""in[-1/2,0)`
(e ) `x in [-3 4]or -3 le x le 4`
Now for `1/x `to get defined ,we must have `-3 le x lt 0 ` or `0 lt x le 4`
`rArr -1/3 ge 1/xgt -ooor 1/4 le 1/x""lt oo`
`rArr1/x""in(-oo,1/3]CUP[1/4,oo)`


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