1.

Find the value of 100 J on a system which has 20 cm, 250g and half minute as fundamental units of length, mass and time.

Answer» Correct Answer - `9xx10^6 new units`
Joule is SI unit of work ` = [ML^2T^(-2)]`
`:. a = 1, b =2, c= -2`
To conver SI system to new system, we write
`M_1 =1kg, L_1 =1m, T_1 = 1s, n_1 =100J`
`M_2 = 250g , L_2 =20cm ,`
`T_2 =(1)/(2) min = 30s,n_2 = ?`
`n_2 = n_1 ((M_1)/(M_2))^a ((L_1)/(L_2))^b ((T_1)/(T_2))^c`
`=100((1kg)/(250g))^1((1m)/(20cm))^2 ((1sec)/(30sec))^(-2)`
`=100xx((1000g)/(250g))((100cm)/(20cm))^2xx30^2`
`= 100xx4xx5^2xx30^2`
`=9xx10^6 "new units"]`


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