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Find the value of (– 16)1/4 |
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Answer» (–16) = 16(–1) = 16(cosπ + isinπ) = 24(cos(2k + 1)π + isin(2k + 1)π], k ∈ z (–16)1/4 = (24)1/4[cos(2k + 1)π + i sin (2k + 1)π]1/4 = 2cos(2k + 1)π/4, k = 0, 1, 2, 3 The value of (–16)1/4 is 2cos(2k + 1)π/4, k = 0, 1, 2, 3 |
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