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Find the value of 5\(\frac{1}{2}\), 5\(\frac{1}{4}\), 5\(\frac{1}{8}\) … up to infinity. |
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Answer» We have 5\(\frac{1}{2}\). 5\(\frac{1}{4}\). 5\(\frac{1}{8}\) … ∞ = 5[\(\frac{1}{2}\)+ \(\frac{1}{4}\) + \(\frac{1}{8}\) +⋯∞] = \(5\bigg[\frac{\frac{1}{2}}{1-\frac{1}{2}}\bigg]\) \(\bigg[\) ∴ \(\frac{1}{2}\) + \(\frac{1}{4}\) + \(\frac{1}{8}\) + ⋯ ∞ = \(\frac{\frac{1}{2}}{1-\frac{1}{2}}=1\bigg]\) = 51 = 5 |
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