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Find the value of `a` if `[(a-b,2a+c),(2a-b,c+d)]=[(-1,5),(0,13)]` |
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Answer» With the given equation, `a-b = -1=> a = b-1->(1)` `2a+c = 5` `2a-b = 0 => a = b/2->(2)` `c+d = 13` From (1) and (2), `b-1 = b/2` `=>b/2 = 1=> b = 2` Putting value of `b` in (1), `a = 2-1 =>a = 1` |
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